Hello everyone,
I want to install both the x64 and the x86 version of an executable on the
harddisk, no matter if the machine is x86 or x64. But I only want to create
one start menu shortcut for the app, the one that is appropriate for the
target OS where the msi gets installed. How Do I go about that? I tried this
for the component, so the start menu entry for the x86 should not appear on
x86, but unfortunately it appears anyway:
<DirectoryRef Id="INSTALLDIR">
<Component Id='PnPMonComp' Guid='???????????'>
<File Id='PnPMonEXE' Name='PnPMon.exe' LongName='PnPMon.exe'
DiskId='1'
Source='PnPMon.exe' Vital='yes'>
<Shortcut Id="startmenuPnPMon" Directory="ProgramMenuDir"
Name="PnPMon"
LongName="PnPMon" WorkingDirectory='INSTALLDIR'
Icon="PnPMon.exe" IconIndex="0">
<Condition Level="0">NOT VersionNT64</Condition>
</Shortcut>
</File>
</Component>
</DirectoryRef>
How can I create a start menu shortcut conditionally?
Any help appreciated,
--
Stefan Kuhr
--
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