On Nov 26, 2013, at 7:58 AM, Christopher Maynard 
<[email protected]> wrote:

> Maybe the snaplen column should display the actual snaplen value instead of
> “default”?  The GTK version does this too, which I’m also not a fan of, as
> “default” doesn’t actually tell you anything.

In the best of all possible worlds, libpcap - and the pcap file format - would 
have allowed a value of 0 to mean "unlimited", and we wouldn't have to worry 
about code reading pcap files allocating buffers based on the snaplen and never 
changing the buffer size.

Unfortunately, "allocating buffers based on the snaplen and never changing the 
buffer size" is exactly what most versions of libpcap do, and have done going 
back at least to libpcap 0.7 and probably all the way back to 0.4, at least.

This means that a value of 0 in the capture file for "unlimited" would produce 
files that can't be read by many versions of libpcap, and thus by programs 
linked with those versions, and a value of 2^32-1 or 2^31-1 would cause libpcap 
to try to allocate a *huge* chunk of memory, almost certainly failing in 32-bit 
code.

In addition, libpcap has traditionally treated a captured length > 65535 as an 
indication that the record for the packet was corrupt.

So this means we can't *truly* have an "unlimited" snapshot length.

Nevertheless, I definitely think the UI should provide a way to easily tell 
Wireshark "I don't want packets cut short", so they shouldn't have to 
explicitly type "6" "5" "5" "3" "5" to get that; there should be a check box to 
request "largest possible snaplen".

I might also be tempted to display that as "none" - or as the "has snaplen" 
checkbox not being checked and the large value used for that purpose displayed 
but grayed out.
___________________________________________________________________________
Sent via:    Wireshark-dev mailing list <[email protected]>
Archives:    http://www.wireshark.org/lists/wireshark-dev
Unsubscribe: https://wireshark.org/mailman/options/wireshark-dev
             mailto:[email protected]?subject=unsubscribe

Reply via email to