On Aug 19, 2009, at 10:48 AM, divya kothapally wrote:
> Iam trying to add a new buffer using tvb_new_real_data but at the
> time to compiling it is giving me a warning saying ISO C90 forbids
> mixed declarations & code. Does tvb_new_real_data need ISO C99 ??
No, it doesn't need C99.
That's because it doesn't need C99 features such as mixed declarations
and code.
Don't do stuff such as:
char *foo;
...
foo = xxx();
...
tvbuff_t *bar = tvb_new_real_data(...);
Instead, do:
char *foo;
tvbuff_t *bar;
...
foo = xxx();
...
bar = tvb_new_real_data(...);
I.e., put all your declarations at the *beginning* of a block. That's
what C89/C90 require.
___________________________________________________________________________
Sent via: Wireshark-dev mailing list <wireshark-dev@wireshark.org>
Archives: http://www.wireshark.org/lists/wireshark-dev
Unsubscribe: https://wireshark.org/mailman/options/wireshark-dev
mailto:wireshark-dev-requ...@wireshark.org?subject=unsubscribe
