final FeedbackPanel fp=new FeedbackPanel(.....);
fp.setOutputMarkupId(true);

new AjaxSubmitLink(..) { onSubmit(AjaxRequestTarget t) { t.add(fp); }}

-Igor

On 10/2/06, Jaime De La Jara <[EMAIL PROTECTED]> wrote:
In the phonebook app there is an EditContactPage that subclass BasePage that has a feedback panel. To the EditContactPage I added an AjaxSubmitLink that adds an address to a contact, I need to validate the address info in the onSubmit method so if it's invalid display a message in the feedbackpanel (which is outside the form that contains the submitting link). How could I do it?

Thanks.


Jaime.


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