Hello Just a note: Even with the error documented above, the service (and apache) still runs. It doesn't seem to be an issue.
-Joe On Monday, August 6, 2012 9:45:51 AM UTC-5, joe wrote: > > Hi Ales, > thanks for the suggestion. > > I ran pythonservice.exe with the debug option and discovered the first > problem was in my options.py file. I copied the options.py text in the > web2py manual (http://web2py.com/books/default/chapter/29/13) but the > lines: > > ssl_certificate = " > ssl_private_key = " > > are actually a problem because those are unpaired double quotes. Then I > got an error from not having the "profiler_filename" variable in options.py > (the options_std of the latest source has this variable already). The > "options.py" example of the documentation should be updated, because unless > you use > pythonservice.exe -debug > the service fails silently (as far as I can tell). > > > After fixing these problems I now have the problem you were referring to. > "pythonservice.exe > -debug web2py" now yields: > > C:\Python26\Lib\site-packages\win32>pythonservice.exe -debug web2py > Debugging service web2py - press Ctrl+C to stop. > Info 0x400000FF - web2py server starting > ERROR:Rocket.Errors.Port443:Socket USSTPLIION:443 in use by other process > and it won't share. > WARNING:Rocket.Errors.Port443:Listener started when not ready. > > > I want Apache to control web2py. I do not want to have rocket involved. > How do I prevent rocket from starting? > > Thanks > Joe > > > On Friday, August 3, 2012 4:53:43 PM UTC-5, LightDot wrote: >> >> My guess is that you have Apache and Rocket (web2py's internal web >> server) both claiming port 443 at the same time. Do you want to use Apache >> to run web2py or..? >> >> Regards, >> Ales >> >> >> On Friday, August 3, 2012 11:40:34 PM UTC+2, joe wrote: >>> >>> >>> Hello >>> >>> I am running apache on a dedicated windows server (2008). As of this >>> morning, it was running successfully as a process. But it needs to be a >>> service, and that is causing me a 404 error. Basically, apache runs just >>> fine as a service, but when I install and start web2py as a service, it >>> starts, and then immediately stops, no matter what I do. Here is my >>> options.py: >>> >>> import socket, os >>> ip = socket.gethostname() >>> port = 443 >>> password = '<recycle>' >>> pid_filename = 'httpserver.pid' >>> log_filename = 'httpserver.log' >>> ssl_certificate = " >>> ssl_private_key = " >>> numthreads = 10 >>> server_name = socket.gethostname() >>> request_queue_size = 5 >>> timeout = 10 >>> shutdown_timeout = 5 >>> folder = os.getcwd() >>> >> --
