record = db(db.videos).select(orderby=~db.videos.hits).first()
On Mon, Mar 26, 2012 at 1:11 PM, Hassan Alnatour <halna...@gardeniatelco.com
> wrote:
> Dear ALL ,
>
> I have a Table like this :
>
> db.define_table('Videos',
> Field('Title'),
> Field('File','upload'),
> Field('Hits','integer'))
>
>
> how can i get the record with the highest Hits ?
>
--
Bruno Rocha
[http://rochacbruno.com.br]
