Hi Alan,
I have tried to decorate two functions. But it notwork as I expected.
Name of the application: queuetest, controller: default.py:
from Queue import *
@service.run
def pp(): # Producer
q.put(request.now.isoformat())
return dict(size=q.qsize())
@service.run
def cc(): # Consumer
s = q.get()
return dict(time=s, size=q.qsize())
@service.run
def pc(): # call producer two times, consumer once
return [pp(), pp(), cc()]
And in db.py:
from Queue import *
q=Queue()
A call of http://127.0.0.1:8000/queuetest/default/call/run/pc returns:
[{'size': 1}, {'size': 2}, {'size': 1, 'time':
'2011-12-04T13:30:33.283000'}]
That's ok.
But I think the next call creates a NEW queue, starting with size 1
[{'size': 1}, {'size': 2}, {'size': 1, 'time':
'2011-12-04T13:33:45.126000'}]
What shall I do to have ONE queue?
Regards, martin
2011/12/2 Alan Etkin <spame...@gmail.com>
> Depending on the type of data maybe you could use web2py services
> interface.
>
> First you define the set/get actions in some of the apps and decorate
> them as services. Then from any application you can consume this
> services for data transactions.
>
> The web2py book covers services and RPC in 9th chapter
>
>
> Apps can share session objects too and you could store a sequence on a
> common session:
> (web2py chapter 4)
> "...One app can load the session of another app using the command:
> 1
> session.connect(request, response, masterapp='appname', db=db)
>
> Here "appname" is the name of the master application, the one that
> sets the
> initial session_id in the cookie. db is a database connection to the
> database
> that contains the session table (web2py_session). All apps that share
> sessions
> must use the same database for session storage. "
>
>
> On Dec 1, 6:06 pm, Martin Weissenboeck <mweis...@gmail.com> wrote:
> > Hi,
> >
> > I want to use one and only one queue (q).
> >
> > Some applications/controllers should act as producers (q.put(item)) and
> > some applications/controllers as consumers (item=q.get()), but with only
> > one queue.
> >
> > How can this be done?
> >
> > Regards, Martin
>
