I'm not sure, but what's the use case? SQLFORM.factory is for creating
forms, not database tables. What would be the result of any linking?
On Tuesday, November 29, 2011 1:14:18 PM UTC-5, Constantine Vasil wrote:
>
> =========================================================
> Instead, though, you might want to explicitly link the two tables:
>
> db.define_table('t_ab_distribution',
> Field('f_distributionname'),
> format='%(f_distributionname)')
>
> db.define_table('t_ab_recipient',
> Field('f_distribution', db.t_ab_distribution))
>
> That will automatically add an IS_IN_DB validator to f_distribution, and
> it will display the f_distributionname in the list due to the
> format='%(f_distributionname)'.
> =========================================================
>
> Can you do the same with SQLFORM.factory?
>
> I consider that SQLFORM.factory creates a virtual table.
>
>
>
>
