Thank you Michele, Chris
On Mon, Sep 19, 2011 at 2:00 PM, Michele Comitini <michele.comit...@gmail.com> wrote: > There is nothing wrong with your code. Maybe it is better to use > find() to get the <geo> tag. > If you have an XSD schema you can use generateDS > http://www.rexx.com/~dkuhlman/generateDS.html > to have a python parser. > > But if you can use the JSON API... much simpler. > > mic > > > 2011/9/19 Chris Rowson <christopherrow...@gmail.com>: >> Anybody using xml.etree? >> >> I asked this question over at the Python tutors group but it seems >> that few people there had experience of it. >> >> I'm trying to access a UK postcode API at www.uk-postcodes.com to take >> a UK postcode and return the lat/lng of the postcode. This is what the >> XML looks like: http://www.uk-postcodes.com/postcode/HU11AA.xml >> >> The function below returns a dict with the xml tag as a key and the >> text as a value. Is this a correct way to use xml.etree? Is there a >> better way of doing this? >> >> Thanks in advance! >> >> Chris >> >> >> def ukpostcodesapi(postcode): >> import urllib >> import xml.etree.ElementTree as etree >> >> baseURL='http://www.uk-postcodes.com/' >> geocodeRequest='postcode/'+postcode+'.xml' >> >> #grab the xml >> tree=etree.parse(urllib.urlopen(baseURL+geocodeRequest)) >> root=tree.getroot() >> results={} >> for child in root[1]: #here's the geo tag >> results.update({child.tag:child.text}) #build a dict >> containing the geocode data >> return results >> >> #example usage (testing the function) >> results = ukpostcodesapi('hu11aa') >> print results['lat']+' '+results['lng'] >> >
