After reading this again and again... this is the intended behavior.
form = SQLFORM(....,hidden=...) causes the hidden fields to be passed
with the submission, no more, no less. form.accepts(...) is not
intended to read the received hidden fields and move them into
form.vars. The reason is security. hidden fields can be tampered with.
So you have to do:
form.vars.a = request.vars.a # this will move the hidden field a (if
exists) into the form
form = SQLFORM(..., hidden=dict(a='b'))
In the future we may consider having digitally signed hidden fields.
On Aug 30, 12:43 pm, Cliff <cjk...@gmail.com> wrote:
> Hmmm.
>
> I'm on 1.98.2.
>
> This needs more investigation, but I can't do it today.
>
> On Aug 30, 8:39 am, DenesL <denes1...@yahoo.ca> wrote:
>
>
>
>
>
>
>
> > SQLFORM with hidden fields works fine in 1.98.2:
>
> > # model
> > db.define_table('dog',
> > Field('name'),
> > Field('age', 'integer')
> > )
>
> > # controller
> > def newdog():
> > form = SQLFORM(db.dog, fields=['name'], hidden={'age': 1})
> > if form.accepts(request, session):
> > response.flash = 'ok'
> > elif form.errors:
> > response.flash = 'not ok'
> > return dict(form = form)
>
> > Any new entry in the dog table will have the age field set to 1.
