db.dog.owner.represent = lambda value, row: db.person(value).name Value is the value of the current field, in this example dog owner is an id of the person for example "1", so to display person name I have to pass this value to search a person with this id: db.person(value).name.
Row is the all row of the current record, perhaps for this example is not need it. But for example suppose I have to list dogs name blast his age. db.dog.name.represent = lambda value, row: '%s (%s)'%(value, row.age) Result: Name ------------------- doggy (2) gog (12) 2011/8/26 Johann Spies <johann.sp...@gmail.com> > Thanks. > > It will be very helpful if somebody can update these lines in the book > because it still not clear to me how to use the new syntax in each of these > instances. I still do not know how 'record' is defined here. > > db.mytable.name.represent = lambda name: name.capitalize() > > > db.mytable.other_id.represent = lambda id: db.other(id).myfield > > > > db.mytable.some_uploadfield.represent = lambda value: \ > > > > A <http://web2py.com/book/default/docstring/A>('get it', _href=URL > <http://web2py.com/book/default/docstring/URL>('download', args=value)) > > > > I have no idea how to use 'record' e.g. in your example of the new grid: > > db.dog.owner.represent = lambda x,record: db.person[x].name > > is not correct > > Regards > Johann > -- > May grace and peace be yours in abundance through the full knowledge of > God and of Jesus our Lord! His divine power has given us everything we need > for life and godliness through the full knowledge of the one who called us > by his own glory and excellence. > 2 Pet. 1:2b,3a > > -- http://martin.tecnodoc.com.ar
