is it perhaps possible to solve it with: IS_EXPR ??? if yes, how? thanks
On 5 Jan., 23:51, pk <peter.kirch...@youngdesigners.de> wrote: > hi thanks for your help but i still get this: > > friends.id friends.userid friends.hauptperson friends.freund > friends.freundseit friends.bestaetigt > 9 5 nueva_vido makir 2011-01-04 18:09:46 False > 11 5 nueva_vido makir 2011-01-05 23:47:54 False > > with: db.friends.freund.requires = > IS_NOT_IN_DB(db(db.friends.hauptperson==request.vars.hauptperson),db.friend > s.freund) > > and how can i say: > db.friends.freund.requires=IS_IN_DB(db,'auth_user.user_name') without > the self user name??? > > thanks so much. > peter > > On 5 Jan., 21:05, DenesL <denes1...@yahoo.ca> wrote: > > > > > > > > > If you want the combination of two fields a,b from table t to be > > unique then use: > > > db.t.b.requires = IS_NOT_IN_DB(db(db.t.a==request.vars.a),db.t.b)
