you need in db.py auth.settings.allow_basic_login = True
it defaults to False On Apr 5, 9:21 pm, Alexei Vinidiktov <alexei.vinidik...@gmail.com> wrote: > Hello, > > I'm trying to make a desktop client written in Python 2.5 (on Windows) > communicate with a web2py 1.76.5 based app using services. It works > fine with services that don't require authentication, but I was > wondering if I could make it authenticate the user with Basic > authentication. > > I've read in the Python docs that xmlrpclib supports Basic authentication: > > " > Both the HTTP and HTTPS transports support the URL syntax extension > for HTTP Basic Authentication:http://user:p...@host:port/path. The > user:pass portion will be base64-encoded as an HTTP `Authorization' > header, and sent to the remote server as part of the connection > process when invoking an XML-RPC method. > " > > In my modified Welcome web2py app I've added the setting > auth.settings.allow_basic_authentication = True in > welcome/models/db.py > > I've decorated the private_call action like so: > > @auth.requires_login() > def private_call(): > return private_service() > > And I've added a test action getstring: > > @private_service.xmlrpc > def getstring(): > if auth.is_logged_in(): > return "logged in!" > else: > return "not logged in!" > > In my desktop app I'm calling the service like this: > > self.server = > xmlrpclib.Server("http://myem...@gmail.com:mypassw...@127.0.0.1:8000/welcome/default/private_call/xmlrpc";) > print self.server.getstring() > > and I'm getting this traceback: > > Traceback (most recent call last): > File "C:\Users\Alexei\Documents\wxPython\Boa\xml_rpc_test\Frame1.py", line > 137 > , in OnButton4Button > print self.server3.getstring() > File "C:\Python25\lib\xmlrpclib.py", line 1147, in __call__ > return self.__send(self.__name, args) > File "C:\Python25\lib\xmlrpclib.py", line 1437, in __request > verbose=self.__verbose > File "C:\Users\Alexei\Documents\wxPython\Boa\xml_rpc_test\Frame1.py", line > 185 > , in request > headers > xmlrpclib.ProtocolError: <ProtocolError for myem...@gmail.com:mypassword@ > 127.0.0.1:8000/welcome/default/private_call/xmlrpc: 303 SEE OTHER> > > I'm obviously doing something wrong. Could you point me in the right > direction? > > Thanks. > > -- > Alexei Vinidiktov -- You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to web...@googlegroups.com. To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/web2py?hl=en.
