I suspect the problem is that you hardcoded a filename and if a second
requests arrives it conflicts with the previous one. You may need file
locking or using tempfile or stringio. This
> exec('from applications.%s.modules import updatexml as xml' %
> request.application)
> reload(xml)
could also be a timeout issue. Does it take long to make the xml?
btw can be replaced by
xml = local_import('updatexml',force=True)
On Feb 2, 4:45 am, Oguz Yarimtepe <oguzyarimt...@gmail.com> wrote:
> In my application i have a updatexml.py under modules directory and at
> the controller i am calling it as
>
> exec('from applications.%s.modules import updatexml as xml' %
> request.application)
> reload(xml)
> result = ta.write()
> return result At the updatexml i have something like: import os def
> write(): try: file_path =
> "C:\\web2py\\applications\\bar\\static\\beverages.xml"
> os.unlink(file_path) f = file(file_path, "w") s = '<?xml version="1.0"
> encoding="UTF-8"?>\n\n' f.write(s) So i am trying to create an xml. But
> at the f.write part it stops executing and i never see the wtite
> function finished. What can be the problem?
--
You received this message because you are subscribed to the Google Groups
"web2py-users" group.
To post to this group, send email to web...@googlegroups.com.
To unsubscribe from this group, send email to
web2py+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/web2py?hl=en.
