like request.accept(keepvalues=True)... but only if there was an error.

-Thadeus





On Sat, Jan 9, 2010 at 11:32 PM, mdipierro <mdipie...@cs.depaul.edu> wrote:
> You can simplify your code
>
> def diag_form():
>    form = SQLFORM(db.socdiag, request.args(0), deletable=True)
>    if form.accepts(request.vars, session):
>        response.flash = 'form accepted'
>    elif form.errors:
>        # (1)
>        response.flash = 'form has errors'
>    return dict(form=form)
>
> I am not sure what you asked. Try insert in (1)
>
>   form.vars.update(request.vars)
>
> OR
>
>   if form.record: form.vars.update(form.record.as_dict())
>
> OR
>
>   [form.vars[key]=db.socdiag[key].default for key in
> db.socdiag.fields]
>
> Does of them solves your problem?
>
> On Jan 9, 5:12 pm, Jeff Bauer <jeffru...@gmail.com> wrote:
>> I'm following another example in the manual using SQLFORM.
>> The code works as advertised.  The only fly in the ointment
>> is when form.errors is True, the user's entry form no longer
>> displays her original values.  I'm assuming there's a simple
>> way to pass the request vars back into form at line 11
>> before return.
>>
>>   1 def diag_form():
>>   2    if len(request.args):
>>   3        records = db(db.socdiag.id==request.args[0]).select()
>>   4    if len(request.args) and len(records):
>>   5        form = SQLFORM(db.socdiag, records[0], deletable=True)
>>   6    else:
>>   7        form = SQLFORM(db.socdiag)
>>   8    if form.accepts(request.vars, session):
>>   9        response.flash = 'form accepted'
>> 10    elif form.errors:
>> 11        response.flash = 'form has errors'
>> 12    return dict(form=form)
>>
>> Jeff Bauer
>> Rubicon, Inc.
>
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