Hi,
I have configurated my CentOS server for web2py support using the guide in the latest book, however i need to exposes the app as default and not welcome/...... I am trying to use mod_rewrite but without any sucess and also if i use routes.py, shows me : mod_wsgi (pid=28201): Target WSGI script '/var/web2py/wsgihandler.py' cannot be loaded as Python module. mod_wsgi (pid=28201): Exception occurred processing WSGI script '/var/web2py/wsgihandler.py'. ..... ..... for (k, v) in symbols['routes_in']: ValueError: too many values to unpack My httpd.conf includes the same lines in the book. In resume i need to load in automatic way: http://server.com/application instead of http://server.com/welcome/default/index Thanks in advance, -------------------------------- Alfonso de la Guarda Centro Open Source(COS) http://delaguarda.info http://alfonsodg.wordpress.com Agenda:http://tinyurl.com/djmjol Telef. 991935157 1024D/B23B24A4 5469 ED92 75A3 BBDB FD6B 58A5 54A1 851D B23B 24A4 -- You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to web...@googlegroups.com. To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/web2py?hl=en.
