The alias translates literally into AS <alias> in SQL, therefore it
cannot be an existing table, a field or a reserved database keyword.
On Oct 29, 2:21 am, Richard <richar...@gmail.com> wrote:
> Hello,
>
> I have a table that links to multiple "media" tables so I use
> with_alias().
>
> I found that the following causes an error:
> model = db.media.with_alias('model')
> but this works:
> model = db.media.with_alias('model_z')
>
> I do have a "model" table so they must be conflicting. What
> restrictions does the with_alias() argument have?
>
> Richard
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