Ah, this was the magic. the db.videos.file.store line. It seems to
work just fine now.
On Aug 17, 8:31 am, mdipierro <mdipie...@cs.depaul.edu> wrote:
> The problem is that I do not undestand where curl is putting the
> image.
> If it is not in request.vars.keys() then curl is not doing a multipart
> form submission.
> If the file is in request.body that it will not be parsed and stored
> in request.vars but this:
>
> request.body.seek(0)
> db.videos.file.store(request.body, 'upload.flv')
>
> should work.
> Massimo
>
> On Aug 17, 7:25 am, Ian Reinhart Geiser <ian.gei...@gmail.com> wrote:
>
> > I see this when i return request.vars.keys() I get an empty array.
> > That seems a little off... doesn't it? Could it be that I am missing
> > a step with respects to reading the request object?
>
> > Thanks for your insight so far!
>
> > On Aug 17, 3:18 am, mdipierro <mdipie...@cs.depaul.edu> wrote:
>
> > > This is the best way of doind it. Can you try add
>
> > > print request.vars.keys
> > > request.body.seek(0)
>
> > > ?
>
> > > On Aug 16, 9:56 pm, Ian Reinhart Geiser <ian.gei...@gmail.com> wrote:
>
> > > > Right now im doing this but getting errors:
> > > > @service.run
> > > > def upload_image( camera_uuid ):
> > > > query = (db.cameras.macaddress == camera_uuid )
> > > > camera_id = db(query).select(db.cameras.id)[0]
> > > > db.videos[0]={ 'camera' : camera_id, 'file' : db.videos.file.store
> > > > (request.body, 'upload.flv') }
> > > > return True
>
> > > > The problem is that its generating 0 size files. But the file is
> > > > correct, and is created in the database correctly. Did i miss a step?
>
> > > > I am using the following curl line:
> > > > curl -T
> > > > ~/test.flvhttp://web2py.geiseri.com/HomeCentral/default/call/run/upload_image/c...
>
> > > > I feel like im close...
>
> > > > On Aug 16, 1:55 pm, mdipierro <mdipie...@cs.depaul.edu> wrote:
>
> > > > > Correction. This works but it probaby does not work with upload.
>
> > > > > you may need something like
>
> > > > > @auth.requires_login()
> > > > > def uploadme(): db.mytable.insert(filefield=request.body.read())
>
> > > > > On Aug 16, 12:50 pm, mdipierro <mdipie...@cs.depaul.edu> wrote:
>
> > > > > > if you have:
>
> > > > > > def mycreate(): return dict(form=crud.create(db.mytable))
>
> > > > > > you normally call:http://..../mycreatetogettheform.
> > > > > > You can also call it with
>
> > > > > >http://..../mycreate.json?json=[]
>
> > > > > > where [] is a URLencoded JSONencoded dictionary containing the new
> > > > > > record. The ".json" instructs web2py not to generate the form but to
> > > > > > expect a json input. This is experimental but give it try. Should
> > > > > > work for any page including crud forms.
>
> > > > > > Massimo
>
> > > > > > On Aug 16, 10:53 am, Ian Reinhart Geiser <ian.gei...@gmail.com>
> > > > > > wrote:
>
> > > > > > > Greetings, Currently I have a lovely web form that was fairly
> > > > > > > easy to
> > > > > > > implement with web2py. I now also have cron script that is
> > > > > > > uploading
> > > > > > > snapshots of an image from a webcam to my website. What I would
> > > > > > > like
> > > > > > > to do is have a service url that I could post my image to and
> > > > > > > have it
> > > > > > > automatically be added vs going through the form.
>
> > > > > > > From what I can tell is I would have a run REST url and i would
> > > > > > > read
> > > > > > > the request.body object to get the file. What I am unclear on is
> > > > > > > how
> > > > > > > I might put this on the filesystem and the needed links in the
> > > > > > > database correctly. Do I have to roll my own update code vs
> > > > > > > using the
> > > > > > > DAL?
>
> > > > > > > Thanks in advance!
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