> Yes, I was going to point that out. But if you turn off IS_STRONG for
> login, then it doesn't matter, does it?

Correct.  IS_STRONG is not a default validator for the password field
(only CRYPT) so if you don't have complexity requirements, just avoid
using it.

> There's another reason to turn off IS_STRONG for logins, too: it leaks
> information to an attacker about the nature of the required password
> content, significantly pruning his dictionary.

Good point.

On Aug 3, 7:40 pm, Jonathan Lundell <jlund...@pobox.com> wrote:
> On Aug 3, 2009, at 5:33 PM, mr.freeze wrote:
>
> > Just a quick message to point out that if you use IS_STRONG, you must
> > override Auth's random_password function to match its complexity
>
> Yes, I was going to point that out. But if you turn off IS_STRONG for  
> login, then it doesn't matter, does it?
>
> There's another reason to turn off IS_STRONG for logins, too: it leaks  
> information to an attacker about the nature of the required password  
> content, significantly pruning his dictionary.
>
> I think that the IS_STRONG-login-bypass trick (or something like it)  
> ought to be in the manual under the IS_STRONG entry.
>
> > or
> > users won't be able to login after resetting their password.  Here's
> > what I did in my model:
>
> > class MyAuth(Auth):
> >    def random_password(self):
> >        import string
> >        import random
> >        password = ''
> >        specials=r'!...@#$*?'
> >        for i in range(0,3):
> >            password += random.choice(string.lowercase)
> >            password += random.choice(string.uppercase)
> >            password += random.choice(string.digits)
> >            password += random.choice(specials)
> >        return ''.join(random.sample(password,len(password)))
>
> > auth=MyAuth(globals(),db)
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups 
"web2py-users" group.
To post to this group, send email to web2py@googlegroups.com
To unsubscribe from this group, send email to 
web2py+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/web2py?hl=en
-~----------~----~----~----~------~----~------~--~---

Reply via email to