u_cnt = db.auth_user.id.count().with_alias('user_count') user_count = db(db.auth_user).select(u_cnt, left = ...).first().user_count
or just passing raw SQL as field: user_count = db(db.auth_user).select('count(id) AS user_count', left = ...).first().user_count четверг, 20 августа 2020 г. в 22:27:04 UTC+3, Jim S: > Clemens > > Thanks so much, that worked perfect. I guess I was a little concerned > about the performance, doing the whole select, but then realized that this > should cut down on result set size, so shouldn't matter that much. > > Again, thank you > > -Jim > > > On Thursday, August 20, 2020 at 2:14:26 PM UTC-5, Clemens wrote: >> >> Hi Jim, >> >> I had this issue some time ago and I solved it by the workaround of using >> len(db(query).select()). The count()-method is a little more performant, >> but in my case it didn't matter. If you need the rows object of the select >> for further processing anyway, you can have the len() on the rows object. >> >> It's not perfect, but it works :-) >> >> Best regards >> Clemens >> >> On Thursday, August 20, 2020 at 8:52:15 PM UTC+2 Jim S wrote: >> >>> Hi >>> >>> I'm trying to get the count of records to be returned in a query using: >>> >>> db(query).count() >>> >>> Adding complexity to the situation is that query may sometimes be over >>> multiple tables with need a left clause added. When selecting records you >>> do this by passing the left= parameter inside the .select(). >>> >>> But, you can't pass anything into the .count() method. >>> >>> Has anyone found an efficient way to get a .count() when a left join is >>> in use? >>> >>> -Jim >>> >>> (cross-posting to py4web as well) >>> >>> -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/web2py/3eaf1e26-c8bf-4c33-bae2-d47402f445fbn%40googlegroups.com.