Yarko, what I am saying is that URL() does not add the "http:// 127.0.0.1:8000" prefix.
You can test it out for yourself to see what I mean. On Jul 22, 2:09 pm, Yarko Tymciurak <[email protected]> wrote: > The pattern for URL is: > > URL( application, controller, function, args, vars ) > > if you pass a request variable, it will start from the info in request, and > override what you've supplied with additional arguments. > > For example: > > URL(r = request) > > Will return the URL of the current request;. > > If it ishttp://localhost:8000/welcome/default/index, then > > URL( r=request, f=afterindex) > > will returnhttp://localhost:8000/welcome/default/afterindex > > On Wed, Jul 22, 2009 at 3:57 PM, Bottiger <[email protected]> wrote: > > > Let's say you simply want the URL for a page such as > > >http://127.0.0.1:8000/welcome/default/index > > > You can use URL(f='index') but it gives you a somewhat relative path. > > > /welcome/default/index > > > So what is the best way to go about adding thehttp://127.0.0.1:8000 > > prefix for the entire website? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---
