What are you trying to do? That code should work fine in web2py, as it's 
just Javascript. You just need to have it call a web2py URL. Of course, 
web2py includes some built-in mechanisms for handling Ajax requests, such 
as the ajax() Javascript function and the LOAD() helper to create Ajax 
components.

Anthony

On Tuesday, June 4, 2019 at 3:23:11 PM UTC-4, Ben Duncan wrote:
>
> Ok, the following is code from w3 schools:
> https://www.w3schools.com/js/js_ajax_intro.asp
>
> The code is as follows :
>
> <!DOCTYPE html>
> <html>
> <body>
>
> <div id="demo">
> <h2>The XMLHttpRequest Object</h2>
> <button type="button" onclick="loadDoc()">Change Content</button>
> </div>
>
> <script>
> function loadDoc() {
>   var xhttp = new XMLHttpRequest();
>   xhttp.onreadystatechange = function() {
>     if (this.readyState == 4 && this.status == 200) {
>       document.getElementById("demo").innerHTML =
>       this.responseText;
>     }
>   };
>   xhttp.open("GET", "ajax_info.txt", true);
>   xhttp.send();
> }
> </script>
>
> </body>
> </html>
>
> The question is how do I get this code to run under web2py ?
>
> Thanks ...
>
> *Ben Duncan*
> DBA / Chief Software Architect 
> Mississippi State Supreme Court
> Electronic Filing Division
>

-- 
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
--- 
You received this message because you are subscribed to the Google Groups 
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to web2py+unsubscr...@googlegroups.com.
To view this discussion on the web visit 
https://groups.google.com/d/msgid/web2py/9b9fa219-3038-4d61-9206-a5ab134f783e%40googlegroups.com.
For more options, visit https://groups.google.com/d/optout.

Reply via email to