def change_name(row, name):
row.person.update_record(name=name)
The above will update the database and the local Row object.
Anthony
On Friday, April 26, 2019 at 5:00:34 PM UTC-4, Lisandro wrote:
>
> Hi Anthony, thank you for your time.
> I tried the method you suggested, but here is my problem: after calling
> the method, the row object isn't updated.
>
> row = db.person(1)
> row.change_name('Lisandro')
> print(row.name)
>
> This doesn't print "Lisandro".
> Instead, it prints the name the person had before the call.
> If I want to print the new name, I have to retrieve the row again like
> this:
>
> row = db.person(1)
> row.change_name('Lisandro')
> row = db.person(1)
> print(row.name)
>
> I was wondering if it was possible to avoid having to retrieve the record
> again.
>
>
> El viernes, 26 de abril de 2019, 17:16:10 (UTC-3), Anthony escribió:
>>
>> def change_name(row, name):
>> db(db.person.id == row.person.id).update(name=name)
>>
>> db.define_table('person',
>> Field('name'),
>> Field.Method('change_name', change_name))
>>
>> row = db.person(1)
>> row.change_name('Lisandro')
>>
>> Anthony
>>
>> On Friday, April 26, 2019 at 12:21:28 PM UTC-4, Lisandro wrote:
>>>
>>> I've been working with Virtual Fields for a while, but now I'm
>>> wondering, how could I write a Virtual Field method that modifies the row
>>> itself?
>>>
>>> I mean, I would like to do something similar that what the
>>> .update_record() method does. When you call row.update_record(), the row
>>> object is updated with the new values.
>>>
>>> I've tried returning the row object in the method definition function
>>> but it doesn't work.
>>>
>>> I'm wondering, is it even possible to implement something like that? Any
>>> comment or suggestion will be much appreciated.
>>>
>>> Thanks!
>>> Warm regards,
>>> Lisandro.
>>>
>>
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