I don't see any code that checks for record change, but you could do something like:
elif request.args and request.args[0] == 'edit': if request.vars.modified_on != str(form.record.modified_on): session.flash = 'Record change detected. Please try again.' redirect(URL(args=request.args, vars=request.get_vars)) That will redirect to the same URL, which will load the same record (with the updated data), and show the message after redirect. Anthony On Wednesday, March 27, 2019 at 3:06:16 PM UTC-4, João Matos wrote: > > This is my code for the another table (it has the same situation, but > without using a SQLFORM.factory). > I posted this instead of the SQLFORM.factory, because it is simpler code. > > My index function contains the grid > > grid = SQLFORM.grid( > query, > csv=False, deletable=False, details=False, > links=[ > lambda row: A( > SPAN(T('Delete'), _class='buttontext button', _title= > 'Delete'), > _href=URL('get_approval', args=[row.id], > user_signature=True), > _class='button btn btn-default btn-secondary', > ), > ], > onvalidation=on_validation, # Form only. > orderby=db.client.name, > paginate=session.auth.user.pagination, > # represent_none='', # Grid and view form only. > ) > > > if 'edit' in request.args: > form = grid.update_form > form['hidden'].update(modified_on=form.record.modified_on) > > My onvalidation function > > if request.args and request.args[0] == 'new': > # Fix for SQLite instead of for_update=True. When for_update is > # fixed for SQLite, only the first SELECT in the function should > # have for_update=True. > while True: > try: > # SQLite only does database lock. > db.executesql('BEGIN IMMEDIATE TRANSACTION') > break > except sqlite3.OperationalError: > sleep(0.5) > elif not db.client(request.vars.id).is_active: > session.flash = T('Record was deleted while you were editing.') > redirect(URL(user_signature=True)) > elif request.post_vars.modified_on != str(db.client(request.vars.id). > modified_on): > form.errors.code = T('Record was changed while you were editing. ' > 'Press F5 to refresh and press Resend in the > ' > 'browser question.') > elif form.vars.delete_this_record: > # Fix for SQLite instead of for_update=True. When for_update is > # fixed for SQLite, only the first SELECT in the function should > # have for_update=True. > while True: > try: > # SQLite only does database lock. > db.executesql('BEGIN IMMEDIATE TRANSACTION') > break > except sqlite3.OperationalError: > sleep(0.5) > > db.client(request.vars.id).update_record( > cancel_approved_by=auth.user_id, > canceled_by=auth.user_id, > canceled_on=request.now, > is_active=False, > ) > > db.commit() > > session.flash = T('Done.') > redirect(URL(user_signature=True)) > elif request.args and request.args[0] == 'edit': > # Fix for SQLite instead of for_update=True. When for_update is > # fixed for SQLite, only the first SELECT in the function should > # have for_update=True. > while True: > try: > # SQLite only does database lock. > db.executesql('BEGIN IMMEDIATE TRANSACTION') > break > except sqlite3.OperationalError: > sleep(0.5) > > > > quarta-feira, 27 de Março de 2019 às 18:47:33 UTC, Anthony escreveu: >> >> Need to see your code. >> >> On Wednesday, March 27, 2019 at 2:47:01 PM UTC-4, João Matos wrote: >>> >>> You mean to update the editing form with the new values from the record >>> on the db without telling the user to press F5? >>> How can I do it? >>> >>> Thanks. >>> >> -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.