You have 3 options: - Simple option: make sure query to build the the table is generated after form.accept - Simpler option: redirect(URL(r=request,args=request.args)) after form.accept - Complex but faster solution: use ajax to render the form. Will re1uire lots of changes in your code.
On Jul 15, 9:53 am, DenisBY <denis....@gmail.com> wrote: > I'm sure this question was asked but couln't find it. > I have form like this (it looks like table): > a | a | a | ... > ----------------- > b | b | b | ... > ----------------- > c | c | c | ... > ---------------- > _ | _ | _ | _ > [submit] > > where b and c is old records and _ is the form where I can enter new > data. > after entering data end pressing submit 'flash' inform me that > everything is ok but I can't see my new record. I have to reload page > (btw only by pressing enter at address bar, else firefox asks me to > resend form) > how to see my new record w/o reloading page (ajax maybe) or how to > reload page? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py Web Framework" group. To post to this group, send email to web2py@googlegroups.com To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---