I have the following link in a view: {{=A('TaC', _href='https://static.domain.com/files/Terms_and_Conditions.pdf', _target="_blank", vars=dict(attachment=True))}}
I want to convert it to a menu item ('TaC', False, URL(???)) How do I convert the _href to a URL() Kind regards Annet -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.