I have tried
form = SQLFORM.grid(db.qr_info,
showblob=True,
)
and I got:
<type 'exceptions.TypeError'> grid() got an unexpected keyword argument
'showblob'
What is wrong?
Version
2.16.1-stable+timestamp.2017.11.14.05.54.25
(läuft auf nginx/1.10.0, Python 2.7.12)
Am Montag, 20. März 2017 19:52:53 UTC+1 schrieb Jordan Myers:
>
> Hello,
>
> I am trying to display a Field that has type 'blob' in a SQLFORM.grid. The
> data is NOT user-uploaded, thus I cannot use the typical uploadfield +
> request.download pattern. I am using blob because I need to store important
> algorithm-generated data that is too large to fit in the 'text' field type.
> I would like it to display a link to a handler.
>
> I tried a simple test case model
>
>
> db.define_table('blob_test',
> Field('blob_field', 'blob', readable=True,
> represent=lambda value, row: A('link',
> _href=URL('handler', args=[row.id]))
> )
> )
>
>
> #and in the controller:
>
> def blob_grid():
> response.view = 'generic.html'
> grid = SQLFORM.grid(db.blob_test.id > 0)
> return dict(grid=grid)
>
>
> The result is that the controller does not display the link, and indeed the
> entire column is overtaken by the default view/edit/delete buttons provided
> by grid.
>
>
> <https://lh3.googleusercontent.com/-WzURnD6J-gg/WNAkBA3OXRI/AAAAAAAAATw/e-ft-MN-wZ0mpln8k5CiONkzBslFepsxgCLcB/s1600/blob_grid.png>
>
>
> Interestingly, the appadmin display of the table does have the represent link
> as intended.
>
>
> <https://lh3.googleusercontent.com/-zHvXKP8aHWM/WNAkJuVI3XI/AAAAAAAAAT0/BDeM8atNGksOBSoQv9G43Cdbgr_FVBvwwCLcB/s1600/blob_admin.png>
>
>
>
>
> How can I have this representation work for SQLFORM.grid? Thanks.
>
>
>
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