Include the header values in a dictionary:
```
raise HTTP(303,location="url",{HEADER_TEST:True})
```
________________________________________
Kiran Subbaraman
http://subbaraman.wordpress.com/about/
On 19-Jan-18 6:19 PM, vince wrote:
i tried
raise HTTP(303,location="url",HEADER_TEST=True)
but i can't find the HEADER_TEST header passed, is this still valid
for recent version of web2py?
On Monday, November 28, 2011 at 10:43:00 PM UTC+8, Massimo Di Pierro
wrote:
Anthony's response suggests a better way to solve your problem yet I
can see people wanting to forward headers. This is possible.
redirect(URL(...))
is the same as
raise HTTP(303,location=URL(...))
the named arguments of HTTP are headers so you can do:
raise HTTP(303,location=URL(...),success=True)
or (forward all headers)
raise HTTP(303,location=URL(...),**request.headers)
On Nov 28, 7:15 am, thodoris <pasxi...@gmail.com> wrote:
> I want to do the following:
>
> I want to add a key to response.headers
>
> response.headers['success']='True'
>
> after a successful file upload and also redirect.
>
> The problem is that i also want to redirect after successful upload
> but redirect makes a new reasponse.headers and i lose the key i want
> to add.
>
> Is there a way to solve this?
>
> When upload fails and i don't get redirected i can see my key in the
> headers.
>
> My code is:
>
> @auth.requires_login()
> def upload():
> db.reactable.id.default = request.args(0)
> form=SQLFORM(db.table)
> response.headers['success']='False'
> if form.accepts(request.vars,session):
> response.headers['success']='True'
> session.flash="Record added"
> redirect(URL('index'))
> return dict(form=form)
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