a, i c, thank you so much for your example massimo, that's why my old code
not work because i'm using _href
e.g.
def index():
grid = SQLFORM.grid(db.thing, links=[lambda row:
A('check',_onclick="jQuery.post('%s')" % URL('check',args=row.id))])
#grid = SQLFORM.grid(db.thing, links=[lambda row:
A('check',_href=URL('check',args=row.id) ) ] ) # not work use _onclick =
jQuery.post()
return dict(grid=grid)
thanks and best regards,
stifan
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