On Wednesday, September 14, 2016 at 2:41:28 PM UTC-4, Dave S wrote: > > > > On Wednesday, September 14, 2016 at 11:23:31 AM UTC-7, Anthony wrote: >> >> Not sure what you mean by caching. If your Ajax call updates data on the >> server but doesn't do anything on the client, then nothing will change on >> the page. We'll need to see some code to help. >> >> Anthony >> > > May be worth noting that the LOAD() helper wraps the Ajax call in such a > way that the DOM contents of the named DIV are replaced. >
Sounds like he wants to update individual cells in an HTML table. With LOAD(), you would have to replace the whole table on each Ajax request, which would be an inefficient way to update a single cell. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
