Alternatively you can also look at this: http://www.web2pyref.com/example/routespy-url-rewrite-with-pattern-based-system-used-by-web2pyref-snippet-1
On Monday, July 11, 2016 at 12:19:18 PM UTC-4, Anthony wrote: > > Alternatively, you can see if the parameter-based rewrite system will suit > your needs, as it includes built-in support for language in the URL. Or you > can track the user's chosen language via a cookie rather than the URL > (doesn't help with bookmarking, though). > > Anthony > > On Monday, July 11, 2016 at 12:17:02 PM UTC-4, Anthony wrote: >> >> >> On Monday, July 11, 2016 at 11:46:54 AM UTC-4, Carlos Cesar Caballero >> wrote: >>> >>> And he can't?? wait, I am lost. >>> >>> I need from some url like that: >>> >>> www.mysite.com/lang/ >>> or >>> www.mysite.com/lang/blog >>> or >>> www.mysite.com/lang/category >>> >>> to get 'lang' >>> and do something like: >>> var = get_lang() >>> and late do: >>> T.force(var) >>> >>> But how can I get lang? >>> >> >> You need to write a regular expression to capture the language from the >> incoming URL and then add it as a variable in the query string of the >> rewritten URL (you may need separate rules for the case where the incoming >> URL has vs. does not have an existing query string, as you need to add a >> "?" to create the query string in the latter case, and you need an "&" in >> the former case). >> >> Assuming you name the query string variable "_language", you would get it >> in your code via request._language. Note, you would then have to add the >> _language variable to all of your outgoing URLs (I would write a custom >> url() function to do that automatically). >> >> Anthony >> > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
