You may need URL(..., scheme=True) depending if fancytree is picky or not...
On Mon, Jun 13, 2016 at 4:44 PM, Richard Vézina <ml.richard.vez...@gmail.com
> wrote:
> I not sure it safe or not, but it surely not portable... let say you app
> is not at port 8000...
>
> use web2py to build you url using URL() helper and you just have to assign
> the output of URL() to a js var something like that :
>
> var url = {{=URL(c=controller, args=args, vars=vars)}}
>
> then
>
> source: {url: url},
> ...
>
> Richard
>
> On Mon, Jun 13, 2016 at 4:27 PM, Alex Glaros <alexgla...@gmail.com> wrote:
>
>> the only way I could get fancyTree to work was with "source url"
>> parmeter below. Is that a safe way to create a url and send it a dict item?
>> (Crontroller view_tree works with: request.get_vars.specificTaxonomyFK)
>>
>> // Initialize Fancytree
>> $("#alexTree").fancytree({
>> checkbox: true,
>> selectMode: 3,
>> source: {url: "
>> http://127.0.0.1:8000/ES3/default/view_tree.json/?specificTaxonomyFK={{=specificTaxonomyFK}}
>> "},
>> dataType: "json",
>> postProcess: function(event, data){
>> data.result = convertData(data.response);
>> },
>> select: function(event, data) {
>> window.open(data.node.data.alexLink, "_blank");
>> }
>> });
>>
>> thanks
>>
>> Alex Glaros
>>
>> --
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>> - http://web2py.com
>> - http://web2py.com/book (Documentation)
>> - http://github.com/web2py/web2py (Source code)
>> - https://code.google.com/p/web2py/issues/list (Report Issues)
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>
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