I initially had a code : for records in records: id = record[0] location = record[3] code.... return location with wb2py code as: def consult_p(): code... if list_func: return list_func report = consult_p()
view_consult code: {{while true:}}{{break}} <div class = "well>" code.. <font size ="2.5" {{=XML(report.replace('\n', '<br>'))}}{{break}} {{pass}} This would work well by printing the data from the DB(everything in the row page) but when trying to print a section of the data, say a string, using the same process but with code at sqlite level as follows: import sqlite location = record[3] if id == name2: corpus = [location] words = unidecode([location][0]) sent = [' '.join(words.split())] code... for sentence in sentences1: if x in re.findall(regex code,sentence): return ''.join([" ".join(]sentence1[m-1],j]) for m,j in enumarate(sentences1) if x in re.findall(regex code,j)])## this is to print only a section of the data in location or record[3] from sqlite when running this in web2py, I get the above error. How can I convert this from tuple to list? or at least print the sentence in a web page Regards Maurice -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.