Thank you, Anthony!
I have found the same solution after reading the source code.
Maybe this tip is worth making mention of it in the book?
2016-05-24 17:16 GMT+02:00 Anthony <abasta...@gmail.com>:
> Rather than using the "fields" argument, to suppress a field in the grid,
> just set its "readable" attribute to False (before creating the grid):
>
> db.t1.bb.readable = False
> grid = SQLFORM.grid(db.t1)
>
> Anthony
>
>
> On Tuesday, May 24, 2016 at 8:44:53 AM UTC-4, mweissen wrote:
>>
>> Let's say I have table with two integer fields and one virtual field:
>>
>> db.define_table('t1',
>> Field('aa','integer'),
>> Field('bb','integer'),
>> Field.Virtual('ab', lambda row: row.t1.aa+row.t1.bb),
>> )
>>
>>
>> The SQLFORM.grid works fine:
>>
>> def ab():
>> grid=SQLFORM.grid(db.t1,
>> fields=(db.t1.aa, db.t1.bb, db.t1.ab),
>> user_signature=False,
>> )
>> return locals()
>>
>>
>> But I do not want to show the column bb and I tried:
>>
>> def ab():
>> grid=SQLFORM.grid(db.t1,
>> fields=(db.t1.aa, db.t1.ab),
>> user_signature=False,
>> )
>> return locals()
>>
>>
>> and - of course - now I get a "key error", because the virtual field
>> cannot access db.t1.bb.
>>
>> I understand, that the fields parameter decides, which columns should be
>> displayed AND which columns could be used in expressions, e.g. in a
>> lambda-function. But these columns could be different.
>>
>> My question:
>> How can I use both columns in a function, but without displaying both
>> columns in the grid?
>>
>> Or simple: is it possible to suppress a column in the grid which has been
>> selected in the fields parameter?
>>
>> Regards Martin
>>
>>
>>
--
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