Thank you guys. Michel,
message.set_from('myweb2pyapp.com')
If someone response to the email, how do I retrieve it? I need to log into
my sandgrid account I am guessing. Not sure why sessage.set_form is my app
name.com
On Thursday, April 21, 2016 at 2:00:00 PM UTC-4, Michael Beller wrote:
>
> You can use the sendgrid smtp server or their api.
>
> https://sendgrid.com/blog/which-protocol-should-i-use-to-send-email-smtp-or-rest/
>
> Here is my logic for using their api (I also use mailgun with I like also):
>
> def send_email_via_sendgrid(email_to, email_subject, email_body):
> # https://github.com/sendgrid/sendgrid-python
>
> import sendgrid
> from sendgrid import SendGridError, SendGridClientError,
> SendGridServerError
>
> sg = sendgrid.SendGridClient('<your sendgrid account>', '<your
> sendgrid pwd>', raise_errors=True)
>
> message = sendgrid.Mail()
> message.add_to(email_to)
> message.set_subject(email_subject)
> message.set_html(email_body)
> #message.set_text('Body')
> message.set_from('Your Name <us...@myweb2pyapp.com>')
> #status, msg = sg.send(message)
>
> try:
> sg.send(message)
> # raise SendGridClientError
> except SendGridClientError:
> pass
> except SendGridServerError:
> pass
> finally:
> return_code = response.status
> return locals()
>
>
> On Wednesday, April 13, 2016 at 12:48:13 PM UTC-4, Krishna Bavandlapally
> wrote:
>>
>> Thank you Leonel Câmara.
>>
>> It worked.
>>
>> mail.settings.server = 'smtp.sendgrid.net:587'
>> mail.settings.sender = xxx...@mail.com
>> mail.settings.login = 'sendgrid_username:sendgrid_password'
>> mail.settings.tls = True
>>
>>
>>
>> On Wednesday, 13 April 2016 14:29:16 UTC+5:30, Krishna Bavandlapally
>> wrote:
>>>
>>> How to integrate (default mailing) SendGrid in Web2py ?
>>>
>>
--
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