stumble upon this post. For some reason, this don't work:
*model:*
db.define_table('mytable',
Field('name', type='list:string',requires=IS_IN_SET
(['red', 'blue','yellow']),widget=lambda field, value:
SQLFORM.widgets.checkboxes.widget(field, value,
_style='bootstrap3_inline_factory', label=True)),
Field("roles", "text")
*default:*
db.mytable.roles.show_if = (db.mytable.name.belongs(['red']))
or even:
db.mytable.roles.show_if = (db.mytable.name =='red')
On Tuesday, June 16, 2015 at 7:52:30 AM UTC-4, kecajk...@gmail.com wrote:
>
> Works! Thanks.
> Is it also possible for SQLFORM.factory?
>
> On Wednesday, 10 June 2015 16:06:47 UTC+2, Anthony wrote:
>>
>> Try:
>>
>> db.table1.order.show_if = db.table1.colour.belongs(['red', 'blue'])
>>
>> Anthony
>>
>> On Tuesday, June 2, 2015 at 6:09:20 AM UTC-4, kecajk...@gmail.com wrote:
>>>
>>> Hi,
>>>
>>> I'm using show_if to hide a filed of my form under certain conditions.
>>> Per web2py guide, show_if uses simple query, but it doesn't work for
>>> logical oprators like "and" "or".
>>> In below example i would like to display field "order" just when colour
>>> is set to "blue" or "red".
>>>
>>> db.define_table('table1', Field('colour',
>>> requires=IS_IN_SET(['blue','red','yellow'])), Field('order'))
>>>
>>> ## That works fine
>>> db.table1.order.show_if = (db.table1.colour=='red')
>>>
>>> #that doesn't work returning error " 'Query' object has no attribute
>>> 'tablename'"
>>> db.table1.order.show_if = (db.table1.colour=='red') |
>>> (db.table1.colour=='blue')
>>>
>>> form=SQLFORM(db.table1)
>>>
>>>
>>> Any ideas?
>>>
>>> Also is it possible to use show_if with SQLFORM.factory ? I don't need
>>> database for that form, but i want to use show_if.
>>>
>>> Thanks.
>>>
>>
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