Why would the form submit because you re-load a component that is *inside*
the form? Your form doesn't have a submit button, nor an action or a
method, and nothing in your JS code executes a submit. How exactly do you
expect it to be submitted? It is not clear what you are trying to achieve.
Anthony
On Sunday, December 6, 2015 at 8:50:21 PM UTC-5, Jason Solack wrote:
>
> So in this case i was just wanting to see if the form was submitted when
> reloading the component via:
>
> jQuery('#test_div').get(0).reload()
>
>
> and by printing the request.vars to the terminal i saw that it wasn't. I
> will try your method $.web2py.component and see what results
>
> On Sunday, December 6, 2015 at 8:14:35 PM UTC-5, Anthony wrote:
>>
>> On Sunday, December 6, 2015 at 7:15:04 PM UTC-5, Jason Solack wrote:
>>>
>>> Sorry i'm not clear! I'm trying to break up a reporting site and my
>>> initial idea was to use several LOAD components where in the past i was
>>> using ajax calls. I like the component framework as it seems i can return
>>> HTML templates... it just feels cleaner.
>>>
>>> I have this component within the form, but i could keep all the
>>> components outside the form if that is required to have them passed to
>>> their corresponding controller.
>>>
>>> Another quick question on components. Is there a way to wait for them
>>> to be loaded until called upon or must they be all loaded on the initial
>>> page load?
>>>
>>
>> Still not quite clear what you are trying to do with the form (as it has
>> no action nor submit button). Anyway, you can always manually load and/or
>> reload a component as follows:
>>
>> First, create a div:
>>
>> <div id='mycomponent'></div>
>>
>> Then load a component into the div via:
>>
>> $.web2py.component('{{=URL('controller', 'function.load')}}',
>> 'mycomponent');
>>
>> Anthony
>>
>>
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