Hello
So I managed to put link and create it but now I have a probelm getting the
id of the record I want to deal with
links = [lambda row: A('',_class='glyphicon glyphicon
glyphicon-remove-sign',
callback=URL('settings','deactivate',vars=dict(table='skills',field =
'sk_status', value = form.vars.id )))]
how do i get sqlform grid record to send it to my function???
Anthony this is my function
I have to change field status in a table. We have more than one status
(active, pending, deleted archived) so I couldnt use the web2py default
funciton as true or false
since we name our filed status based on table i have to send table name and
table field that is why this kind of function because i use it in different
tables
@auth.requires_login() def deactivate(): ##Aktiviramo delavca ko user
klikne na activate user = auth.user_id org = db(db.auth_user.id ==
user).select(db.auth_user.organization)[0]["organization"] #Worker je id
zaposlenenga ki ga damo v aktiven id = request.vars["id"] table =
request.vars["table"] field = request.vars["field"] print request print id
query = db(db[table].id == id).update(**{field: 1}) return locals()
Thank you
2015-09-18 18:41 GMT+08:00 Anthony <abasta...@gmail.com>:
> Yes, but what problem do you observe? Are the URLs not getting generated
> properly? Is the value not available in request.get_vars? What happens when
> you click? Can you show the code of the action associated with that URL?
>
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