on sqlhtml.py line 2394:
...
oExp = clazz(rows)
export_filename = \
request.vars.get('_export_filename') or 'rows'
filename = '.'.join((export_filename, oExp.file_ext))
response.headers['Content-Type'] = oExp.content_type
response.headers['Content-Disposition'] = \
'attachment;filename=' + filename + ';'
...
seems to be the code responsible for the download filename, and it is
trying to find a filename suggestion on *request.vars.get('_export_filename')
*!?
El lunes, 10 de agosto de 2015, 14:49:23 (UTC-4), Yoel Benitez Fonseca
escribió:
>
> In sqlhtml.py:
>
> class ExportClass(object):
> label = None
> file_ext = None
> content_type = None
>
> def __init__(self, rows):
> self.rows = rows
> ...
>
> Is there a way to suggest a filename to the client ?
>
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