Its supposed to be the same. But this does not work. All i am doing is checking if this user: db.auth_user(id) wants to use an aliasname or not. Of which aliasname is a field in auth_user table
On Friday, 12 June 2015 15:11:19 UTC+2, zimani wrote: > > I apologise, i have been trying too many things: > > > me=db(db.auth_user.id == > id).select(db.auth_user.usealiasname).first().usealiasname > > This is what i currently have. > > > On Friday, 12 June 2015 14:54:57 UTC+2, Anthony wrote: >> >> >> >> On Friday, June 12, 2015 at 8:36:43 AM UTC-4, zimani wrote: >>> >>> I have this code: >>> >>> def author(id): >>> if id is None: >>> return "Unknown" >>> else: >>> user = db.auth_user(id) >>> me=db(db.auth_user.id == >>> id).select(db.auth_user.usealiasname).first().usealiasname >>> if me==False: >>> return '%(first_name)s %(last_name)s' % user if user else '' >>> else: >>> return '%(aliasname)s' % user if user else '' >>> >>> >>> I want to check if the user with a particular 'id' wants to use an >>> aliasname or real names. However it wont work. i know for sure this line is >>> the one that is wrong because without the condition it prints properly. can >>> somebody help. i am sure its simple but i cannot seem to figure it out. >>> >>> me=db(db.auth_user.id == >>> auth.user_id).select(db.auth_user.usealiasname).first().usealiasname >>> >> >> In the function code you showed above, you have db.auth_user.id == id, >> but here you have db.auth_user.id == auth.user_id. Which code are you >> actually using? Is id supposed to be the same value as auth.user_id? If so, >> your "me" variable is unnecessary, as you are simply fetching the same >> record that you have already stored in the "user" variable. >> >> Anthony >> > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
