Niphlod!! This is perfect! Exactly what I was looking for. Thank you!
On Thursday, June 11, 2015 at 4:53:52 AM UTC-4, Niphlod wrote:
>
> use the links argument
>
> links = [
> ...........
> dict(header='additional buttons', body=lambda row: BUTTON(.....)
> if row.needs_button == 0 else ''
> )
> ]
>
> On Thursday, June 11, 2015 at 12:45:29 AM UTC+2, LoveWeb2py wrote:
>>
>> I should have been more specific. I meant I want to create a SQLFORM.grid
>> button and only have it show if a row.id value is present
>>
>> On Wednesday, June 10, 2015 at 5:42:33 PM UTC-4, LoveWeb2py wrote:
>>>
>>> I'd like to create a SQLFORM button, but only show the button if a value
>>> is present in the cell. Is this possible? I'm thinking of creating a
>>> function that will check to see if each record has a value present in the
>>> field
>>>
>>> for example:
>>>
>>> define_table('my_sqldata',
>>> Field('name',
>>> Field('address',
>>> migrate=False)
>>>
>>> if my_sqldata.address != '' then show icon in SQLFORM else: show nothing
>>>
>>> Is this possible?
>>>
>>
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