use the power, luke! aside from various networking libraries out there, the problem is rather simple.... what you're getting back is the "alphabetical order" . what you need instead is to sort every triplet as an integer. In reality, python strings for ip addresses are good enough, if taken separately, i.e. 1 is lower than 10 even if "1" and "10" are strings.
so, to order your ip addresses, you just split every ip address by "." given a list of myips = [ '192.168.4.1', '192.168.1.10', '192.168.1.11', ] what_you_want = sorted(myips, key=lambda x: x.split('.')) -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.