This will always go to a new page because you're following a link. You need 
to make this an ajax call associated with the onclick of the button. Then 
you can simply use response.flash to use the regular alerts web2py already 
provides or response.js and you don't even need to return anything else.

-- 
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
--- 
You received this message because you are subscribed to the Google Groups 
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to web2py+unsubscr...@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.

Reply via email to