How about this?
L1, L2 = db.l1_categories, db.l2_categories
categories=db(L2.l1_categories==L1.id).select(L2.ALL, orderby=L1.name
<http://db.l2_categories.l1_category.name/>)
On Sunday, 11 January 2015 15:57:47 UTC-6, Gael Princivalle wrote:
>
> Hello all.
>
> We talk about a categories system for a vertical menu.
>
> Here is my model:
> db.define_table('l1_categories',
> Field('name'),
> format = '%(name)s')
>
> db.define_table('l2_categories',
> Field('l1_category', 'reference l1_categories'),
> Field('name'),
> format=lambda row: '%s - %s' % (row.l1_category.name, row.name))
>
> My controller:
> def products():
> categories=db().select(db.l2_categories.ALL, orderby=
> db.l2_categories.l1_category.name)
> return dict(categories=categories)
>
> I need to order categories by l1_category.name.
> Like that it's ordered by l1_category.id.
> Someone knows how I can order these categories by l1_category.name ?
>
> Thanks, regards.
>
>
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