An old post to solve a 2014 problem. Thanks for sharing! :)
El miércoles, 2 de noviembre de 2011 16:27:23 UTC+1, Vineet escribió:
>
> Recently, I wrote this function for my purpose.
> See if this helps you.
> Assuming that argument 'dte' input format is -->> "03-11-2011"
>
> [CODE]
> import datetime, string
>
> def str_to_dt(dte):
> dte = str(dte)
> dte = string.strip(dte)
> if len(dte) == 10:
> y = int(dte[6:])
> m = int(dte[3:5])
> d = int(dte[:2])
> return datetime.date(y, m, d)
> [/CODE]
>
> This returns output in "python datetime.date" format.
>
> --Vineet
>
> On Nov 2, 8:19 pm, Omi Chiba <ochib...@gmail.com> wrote:
> > This is more like python question but
> >
> > jj.J2NSD is integer and has value = 20111130 (YYYYMMDD)
> >
> > I want to set the value as default value of FFNSD which is 'date'
> > type.
> >
> > Field('FFNSD', 'date'),
> >
> > I think I need to import datetime and convert from integer or stiring.
> > Is anyone know easy way to do it ?
> >
> > This doesn't work because it set string to date...
> >
> > db.FEDEXFORM.FFNSD.default = str(jj.J2NSD)[0:4]+"-"+str(jj.J2NSD)
> > [4:6]+"-"+str(jj.J2NSD)[6:8]
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