row=db(db.mp3s.keyflag==request.args[0]).select().first()
filename=os.path.join(request.env.web2py_path,"applications",request.application,"uploads",row['mp3'])
response.headers['Content-Type']='audio/mpeg'
return open(filename,'rb')
It works
:) thank you
2014-11-14 12:38 GMT+00:00 António Ramos <ramstei...@gmail.com>:
> but how do i code a controller that accepts the name or other field and
> returns the mp3 saved ?
>
>
> 2014-11-14 12:31 GMT+00:00 Leonel Câmara <leonelcam...@gmail.com>:
>
>> Well if you coded it like that you saved the original filename in the
>> name field, the cloudservice can just use that.
>>
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Resources:
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- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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