For anyone else looking for a similar answer, I solved this by doing the following in my controller:
back_button = A(T('Back'), _href=URL('controller', 'function', user_signature=True), _class='btn') Returned this as part of my dict back to my view and then did the following at the top of the view for "view" pages: {{=back_button}} On Tuesday, September 23, 2014 11:12:14 AM UTC-5, Kyle Flanagan wrote: > > I have a controller that creates a grid off of a table -- very basic grid. > I test to see if the user is "viewing" an item in the grid (if request.args > and request.args[0] == 'view') and if so, I customize the view to present > the information in the grid in a different layout. > > Now, I'd like to add a back button similar to what you get on the standard > view for a grid but without displaying the grid on the 'view' page. > > I know how to create the button in the view, but I'm not sure how to > create the URL since it's using the signature in the link. > > {{=A(T('Back'), _href=URL(????), _class='btn')}} > > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.