Use represent and the tag A helper.

db.table_name.link_field.represent = lambda value, row: A(value,
_href=value)


2014-04-28 13:17 GMT-03:00 <jaw...@gmail.com>:

> Hi
>
> I've created a run-of-the-mill table:
>
> def index():
>     grid = SQLFORM.grid(db.table_name, user_signature=False)
>     return dict(grid=grid)
>
> One of the columns in the table is an actual link - how do I go about
> making this "clickable"?
>
> Thanks!
>
> --
> Resources:
> - http://web2py.com
> - http://web2py.com/book (Documentation)
> - http://github.com/web2py/web2py (Source code)
> - https://code.google.com/p/web2py/issues/list (Report Issues)
> ---
> You received this message because you are subscribed to the Google Groups
> "web2py-users" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to web2py+unsubscr...@googlegroups.com.
> For more options, visit https://groups.google.com/d/optout.
>



-- 
Att.

Carlos J. Costa
Cientista da Computação
Esp. Gestão em Telecom

EL MELECH NEEMAN!
אָמֵן

-- 
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
--- 
You received this message because you are subscribed to the Google Groups 
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to web2py+unsubscr...@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.

Reply via email to