I already know auth.is_logged_in(), but unfortunately when the user enter like visitor, he's not logged in, he just entered at the site without a login.
I need something like a login_onreject, because the visitor actually don't sign up. =/ 2014-02-10 17:22 GMT-02:00 Tim Richardson <t...@growthpath.com.au>: > in your controller, you can access the global variable auth. > > You can ask > auth.is_logged_in() is True if the user is logged in, for example. > auth.user returns a Row telling you who is logged in. > > http://web2py.com/books/default/chapter/29/09/access-control#Authorization > > > > > -- > Resources: > - http://web2py.com > - http://web2py.com/book (Documentation) > - http://github.com/web2py/web2py (Source code) > - https://code.google.com/p/web2py/issues/list (Report Issues) > --- > You received this message because you are subscribed to a topic in the > Google Groups "web2py-users" group. > To unsubscribe from this topic, visit > https://groups.google.com/d/topic/web2py/s2jOtL0niZM/unsubscribe. > To unsubscribe from this group and all its topics, send an email to > web2py+unsubscr...@googlegroups.com. > For more options, visit https://groups.google.com/groups/opt_out. > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
