> > links=[lambda row: A('View',_href=URL('view',args=[db.products,row.id]))], >
First, note that the URL function produces a string, so putting db.products in args is equivalent to str(db.products), which will result in just "products". > def view(table,id): > return dict() > As noted in the book, any function in a controller that accepts arguments is *not* exposed as an action accessible via URL (in other words, it is a private function). To access args passed via a URL (i.e., the part of the URL path that comes after /app/controller/function), you must use request.args (i.e., request.args(0) is the first argument, etc.). Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.